Page updated: March 6, 2021
Author: Curtis Mobley
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# Polarization: Scattering Geometry

This page discusses the geometrical considerations underlying computations of the scattering of polarized light using Stokes vectors. [Note to the reader: This page uses bold face for vectors in 3D space. This shows up well on the web page for Latin letters, but not as well for Greek letters, so use your common sense. The “blackboard” font is used for $4×1$ Stokes vectors ($𝕊$) and $4×4$ rotation ($ℝ$) and Mueller ($𝕄$) matrices.]

As is shown on the Polarization: Stokes Vectors page, the state of polarization of a light ﬁeld is speciﬁed by the four-component Stokes vector, whose elements are related to the complex amplitudes of the electric ﬁeld vector $\mathbf{\text{E}}$ resolved into directions that are parallel (${E}_{\parallel }$) and perpendicular (${E}_{\perp }$) to a conveniently chosen reference plane.

However, there are two versions of the Stokes vector seen in the literature, and these two versions have diﬀerent units and refer to diﬀerent physical quantities. The coherent Stokes vector describes a quasi-monochromatic plane wave propagating in one exact direction, and the vector components have units of power per unit area (i.e., irradiance) on a surface perpendicular to the direction of propagation. To be speciﬁc, the coherent Stokes vector can be deﬁned as (e.g., Mishchenko et al. (2002))

 $𝕊=\left[\begin{array}{c}\hfill I\hfill \\ \hfill Q\hfill \\ \hfill U\hfill \\ \hfill V\hfill \end{array}\right]=\frac{1}{2}\sqrt{\frac{{𝜖}_{m}}{{\mu }_{m}}}\left[\begin{array}{c}\hfill {E}_{o\parallel }{E}_{o\parallel }^{\ast }+{E}_{o\perp }{E}_{o\perp }^{\ast }\hfill \\ \hfill {E}_{o\parallel }{E}_{o\parallel }^{\ast }-{E}_{o\perp }{E}_{o\perp }^{\ast }\hfill \\ \hfill {E}_{o\parallel }{E}_{o\perp }^{\ast }+{E}_{o\perp }{E}_{o\parallel }^{\ast }\hfill \\ \hfill i\left[{E}_{o\parallel }{E}_{o\perp }^{\ast }-{E}_{o\perp }{E}_{o\parallel }^{\ast }\right]\hfill \end{array}\right]\phantom{\rule{0.3em}{0ex}}.$ (1)

Here ${𝜖}_{m}$ is the electric permittivity of the medium (with units of $Farad∕m$ or SI units of ${A}^{2}\phantom{\rule{2.6108pt}{0ex}}{s}^{4}\phantom{\rule{2.6108pt}{0ex}}k{g}^{-1}\phantom{\rule{2.6108pt}{0ex}}{m}^{-3}$), and ${\mu }_{m}$ is the magnetic permeability of the medium ($Henry∕m$ or $kg\phantom{\rule{2.6108pt}{0ex}}m\phantom{\rule{2.6108pt}{0ex}}{s}^{-2}\phantom{\rule{2.6108pt}{0ex}}{A}^{-2}$). Electric ﬁelds have units of $Newton∕coulomb$ or $kg\phantom{\rule{2.6108pt}{0ex}}m\phantom{\rule{2.6108pt}{0ex}}{s}^{-3}\phantom{\rule{2.6108pt}{0ex}}{A}^{-1}$. Thus the elements of the coherent Stokes vector have units of $kg\phantom{\rule{2.6108pt}{0ex}}{s}^{-3}$ or $Watt∕{m}^{2}$ (i.e., irradiance). ${E}^{\ast }$ denotes complex conjugate, hence the components of the Stokes vector are real numbers.

The diﬀuse Stokes vector is deﬁned as in Eq. (1) but describes light propagating in a small set of directions surrounding a particular direction and has units of power per unit area per unit solid angle (i.e., radiance). It is the diﬀuse Stokes vector that appears in The General Vector Radiative Transfer Equation. The diﬀerences in coherent and diﬀuse Stokes vectors are rigorously presented in Mishchenko (2008b).

Authors often omit the $\frac{1}{2}\sqrt{{𝜖}_{m}∕{\mu }_{m}}$ factor in Eq. (1) because they are interested only in relative values such as the degree of polarization, not in absolute magnitudes, but this omission is both confusing and physically incorrect. Units and magnitudes matter! The diﬀerent units of coherent and diﬀuse Stokes vectors, and whether or not the $\frac{1}{2}\sqrt{𝜖∕{\mu }_{m}}$ factor is included in the deﬁnition of the Stokes vector, have subtle but very important consequences in how light propagation across a dielectric interface such as the air-water surface is formulated. The recent paper by Zhai et al. (2012) gives a deﬁnitive discussion of these matters.

### Coordinate Systems

To describe the scattering of polarized light, we must ﬁrst choose coordinate systems and show in detail how to resolve Stokes vectors in these coordinate systems as needed for scattering calculations.

Figure 1 shows the coordinate systems commonly used to resolve Stokes vectors as needed for geophysical scattering calculations. In oceanography, depth and direction are deﬁned in a 3D Cartesian coordinate system with depth measured positive downward from 0 at the mean sea surface. Polar angle $𝜃$ is deﬁned from 0 in the $+\mathbf{\text{z}}$ (or downwelling direction) to $\pi$ in the $-\mathbf{\text{z}}$ (upwelling) direction. $+\mathbf{\text{x}}$ is chosen for convenience, e.g., pointing toward the sun or pointing in the downwind direction (in which case $±\mathbf{\text{y}}$ is the cross-wind direction. As shown in Mobley (2014), using a wind-centered coordinate system makes it easier to model a random sea surface with diﬀerent along-wind and cross-wind slope statistics.) Azimuthal angle $\varphi$ is measured counterclockwise from $+\mathbf{\text{x}}$ when looking in the $-\mathbf{\text{z}}$ direction. If the Sun is placed in the $+\mathbf{\text{x}}$ azimuthal direction at ${\varphi }_{\text{Sun}}=0$, unscattered rays from the Sun are then traveling in the $-\mathbf{\text{x}}$ direction at $\varphi =180$ deg.

The unit vectors in the directions of increasing $\left(r,𝜃,\varphi \right)$ are

$\begin{array}{lll}\hfill \mathbf{\text{r}}=& sin𝜃cos\varphi \phantom{\rule{0.3em}{0ex}}\mathbf{\text{x}}+sin𝜃sin\varphi \phantom{\rule{0.3em}{0ex}}\mathbf{\text{y}}+cos𝜃\phantom{\rule{0.3em}{0ex}}\mathbf{\text{z}}\phantom{\rule{0.3em}{0ex}},\phantom{\rule{2em}{0ex}}& \hfill \text{(2)}\\ \hfill 𝜗=& cos𝜃cos\varphi \phantom{\rule{0.3em}{0ex}}\mathbf{\text{x}}+cos𝜃sin\varphi \phantom{\rule{0.3em}{0ex}}\mathbf{\text{y}}-sin𝜃\phantom{\rule{0.3em}{0ex}}\mathbf{\text{z}}\phantom{\rule{0.3em}{0ex}},\phantom{\rule{2em}{0ex}}& \hfill \text{(3)}\\ \hfill \phi =& -sin\varphi \phantom{\rule{0.3em}{0ex}}\mathbf{\text{x}}+cos\varphi \phantom{\rule{0.3em}{0ex}}\mathbf{\text{y}}\phantom{\rule{0.3em}{0ex}}.\phantom{\rule{2em}{0ex}}& \hfill \text{(4)}\end{array}$

Let $\xi$ denote a unit vector pointing in the direction of light propagation, as given by angles $\left(𝜃,\varphi \right)$. (In Fig. 1, ${\xi }^{\prime }=\mathbf{\text{r}}$.) The components of $\xi$ are given by

$\begin{array}{lll}\hfill \xi =& {\xi }_{x}x+{\xi }_{y}y+{\xi }_{z}z=\left({\xi }_{x},{\xi }_{y},{\xi }_{z}\right)\phantom{\rule{2em}{0ex}}& \hfill \text{(5)}\\ \hfill \text{where}& \phantom{\rule{2em}{0ex}}& \hfill & \phantom{\rule{2em}{0ex}}\\ \hfill {\xi }_{x}=& sin𝜃cos\varphi \phantom{\rule{0.3em}{0ex}},\phantom{\rule{2em}{0ex}}& \hfill \text{(6)}\\ \hfill {\xi }_{y}=& sin𝜃sin\varphi \phantom{\rule{0.3em}{0ex}},\phantom{\rule{2em}{0ex}}& \hfill \text{(7)}\\ \hfill {\xi }_{z}=& cos𝜃\phantom{\rule{0.3em}{0ex}}.\phantom{\rule{2em}{0ex}}& \hfill \text{(8)}\end{array}$

In radiative transfer theory, direction $\left(𝜃,\varphi \right)$ always refers to the direction of light propagation. Thus light traveling straight down is traveling in the $+\mathbf{\text{z}}$ or $𝜃=0$ direction. To detect radiance in the $\left(𝜃,\varphi \right)$ direction, an instrument is pointed in the viewing direction $\left({𝜃}_{v},{\varphi }_{v}\right)=\left(𝜃-\pi ,\varphi +\pi \right)$, which is sometimes more convenient for plotting. A prime generally denotes an incident or unscattered direction, e.g, ${\xi }^{\prime }$ or $\left({𝜃}^{\prime },{\varphi }^{\prime }\right)$. Unprimed variables denote ﬁnal or scattered directions, e.g. $\xi$ or $\left(𝜃,\varphi \right)$.

There is frequent need to resolve Stokes vectors in directions perpendicular and parallel to a given plane, which can be a meridian plane, a scattering plane in the water volume, or the plane of incident, reﬂected, and transmitted light for light incident onto an air-water or bottom surface. The following conventions deﬁne these unit vectors. Vector $\mathbf{\text{p}}$ denotes a vector parallel to a plane, and $\mathbf{\text{s}}$ denotes a vector perpendicular to a plane (“s” for senkrecht, German for perpendicular). The perpendicular vector $\mathbf{\text{s}}$ is chosen to be in the direction given by the vector cross product of the incident direction crossed with the ﬁnal direction. The parallel vector $\mathbf{\text{p}}$ is then deﬁned as the direction of propagation cross the perpendicular direction. Thus the perpendicular cross parallel directions give the direction of light propagation: $\mathbf{\text{s}}×\mathbf{\text{p}}=\xi$, where $×$ denotes the vector cross product.

For an incident direction ${\xi }^{\prime }$ and the associated Stokes vector ${𝕊}^{\prime }$ speciﬁed in the incident meridian plane, the ﬁrst vector is taken to be $\mathbf{\text{z}}$ and the second is the direction of propagation. Thus ${\mathbf{\text{h}}}^{\prime }\equiv \mathbf{\text{z}}×{\xi }^{\prime }∕|\mathbf{\text{z}}×{\xi }^{\prime }|$ as seen in the right panel of Fig. 1. In this case $|\mathbf{\text{z}}×{\xi }^{\prime }|=\phantom{\rule{2.6108pt}{0ex}}sin{𝜃}^{\prime }$, and ${\mathbf{\text{h}}}^{\prime }={\phi }^{\prime }$. Similarly, ${\mathbf{\text{v}}}^{\prime }\equiv {\xi }^{\prime }×{\mathbf{\text{h}}}^{\prime }=-{𝜗}^{\prime }$, and ${\mathbf{\text{h}}}^{\prime }×{\mathbf{\text{v}}}^{\prime }={\xi }^{\prime }$. Meridian planes are perpendicular to the mean sea surface. The ${\mathbf{\text{h}}}^{\prime }$ vector as just deﬁned is therefore parallel to the mean sea surface and therefore is often referred to as the “horizontal” direction; ${\mathbf{\text{v}}}^{\prime }$ lies in a vertical plane and is correspondingly called the “vertical” direction. For a ﬁnal direction $\xi$ and its Stokes vector $𝕊$ in the ﬁnal meridian plane, the ﬁrst vector is the direction $\xi$ and the second is z. This vector cross product algorithm for specifying perpendicular and parallel directions will be convenient for sea surface reﬂectance and transmission calculations in which light can propagate from one tilted wave facet to another without reference to meridian planes, except for the incident and ﬁnal directions when a photon enters or leaves the region of the sea surface.

The $Q$ and $U$ components of a Stokes vector describe linear polarization with the plane of polarization speciﬁed relative to a particular coordinate system. The $I$ component is the total radiance, and $V$ describes circular polarization; these quantities do not depend on the coordinate system and are invariant under a rotation of the coordinate system. The blue arrows in Fig. 1 represent the plane of oscillation of the electric ﬁeld vector $\mathbf{\text{E}}$ parallel to the meridian plane, i.e. for vertical plane polarization. The components of ${𝕊}^{\prime }={\left[1,1,0,0\right]}^{T}$ as shown thus represent radiance of magnitude $1\phantom{\rule{2.6108pt}{0ex}}W\phantom{\rule{2.6108pt}{0ex}}{m}^{-2}\phantom{\rule{2.6108pt}{0ex}}s{r}^{-1}\phantom{\rule{2.6108pt}{0ex}}n{m}^{-1}$ that is 100% vertically plane polarized.

### Scattering Geometry

The elements of input and output Stokes vectors are deﬁned relative to meridian planes, as described above. However, scattering from an incident direction ${\xi }^{\prime }$ to a ﬁnal direction $\xi$ is deﬁned in terms of the included scattering angle $\psi$ and the scattering plane, as illustrated in Fig. 2. Using Eqs. (5)-(8) to express the incident direction ${\xi }^{\prime }$ and scattered direction $\xi$ in terms of the incident and scattered polar and azimuthal angles gives the scattering angle $\psi$:

$\begin{array}{llll}\hfill cos\psi =& {\xi }^{\prime }\cdot \xi \phantom{\rule{2em}{0ex}}& \hfill & \phantom{\rule{2em}{0ex}}\\ \hfill =& cos{𝜃}^{\prime }cos𝜃+sin{𝜃}^{\prime }sin𝜃\phantom{\rule{0.3em}{0ex}}cos\left(\varphi -{\varphi }^{\prime }\right)\phantom{\rule{0.3em}{0ex}}.\phantom{\rule{2em}{0ex}}& \hfill \text{(9)}\end{array}$

Consider an incident beam of light propagating in direction ${\xi }^{\prime }=\mathbf{\text{r}}$ as in Fig. 1. Direction ${\xi }^{\prime }$ is speciﬁed by polar and azimuthal directions $\left({𝜃}^{\prime },{\varphi }^{\prime }\right)$. Primed variables denote unscattered or incident directions; unprimed variables denote scattered or ﬁnal directions. The $\mathbf{\text{z}}$ axis and the direction of light propagation ${\xi }^{\prime }$ deﬁne the incident meridian plane, part of which is shaded in blue in the right panel of Fig. 1. The $4×1$ (diﬀuse) Stokes vector ${𝕊}^{\prime }={\left[{I}^{\prime },{Q}^{\prime },{U}^{\prime },{V}^{\prime }\right]}^{T}$ for this beam of light is described with reference to “horizontal” and “vertical” directions, $+{\mathbf{\text{h}}}^{\prime }$ and $+{\mathbf{\text{v}}}^{\prime }$ respectively, which were deﬁned above; the superscript T denotes transpose. Note that the horizontal unit vector $+{\mathbf{\text{h}}}^{\prime }$ is perpendicular to the meridian plane, and the vertical vector $+{\mathbf{\text{v}}}^{\prime }$ is parallel to the meridian plane.

To compute how an incident Stokes vector ${𝕊}^{\prime }$ is scattered to a ﬁnal vector $𝕊$, the horizontal and vertical components of ${S}^{\prime }$ in the incident meridian plane must ﬁrst be transformed (“rotated”) into components parallel and perpendicular to the scattering plane. The coordinate system after rotation of ${\mathbf{\text{v}}}^{\prime }$ and ${\mathbf{\text{h}}}^{\prime }$ about the ${\xi }^{\prime }$ axis is labeled ${\mathbf{\text{p}}}^{\prime }$ (parallel to the scattering plane) and ${\mathbf{\text{s}}}^{\prime }$ (perpendicular to the scattering plane). Note that ${\mathbf{\text{s}}}^{\prime }×{\mathbf{\text{p}}}^{\prime }$ still gives the direction of propagation ${\xi }^{\prime }$. As shown in Fig. 2, rotation angle ${\alpha }^{\prime }$ takes ${\mathbf{\text{v}}}^{\prime }$ into ${\mathbf{\text{p}}}^{\prime }$ (and ${\mathbf{\text{h}}}^{\prime }$ into ${\mathbf{\text{s}}}^{\prime }$). In the present discussion, rotation angles are deﬁned as positive for counterclockwise rotations when looking “into the beam,” e.g. in the $-{\xi }^{\prime }$ direction. This is similar to rotations about the $\mathbf{\text{z}}$ axis of Fig. 1 having positive angles $\varphi$ for counterclockwise rotations when looking in the $-\mathbf{\text{z}}$ direction.

When computing single scattering with both ${\xi }^{\prime }$ and $\xi$ being expressed in their respective meridian planes, the rotation angles can be obtained from spherical trigonometry applied to the triangle deﬁned by z, ${\xi }^{\prime }$, and $\xi$, which is shown in the inset in Fig. 2. Given ${𝜃}^{\prime },{\varphi }^{\prime },𝜃,\varphi$, spherical trigonometry gives the rotation angles ${\alpha }^{\prime }$ and $\alpha$ as (e.g., Vol. 2, page 499 of van de Hulst (1980), or page 90 of Mishchenko et al. (2002))

 $cos{\alpha }^{\prime }=\left(cos𝜃-cos{𝜃}^{\prime }cos\psi \right)∕\left(sin\psi sin{𝜃}^{\prime }\right)$ (10)

or

 $sin{\alpha }^{\prime }=-sin𝜃sin\left(\varphi -{\varphi }^{\prime }\right)∕sin\psi \phantom{\rule{0.3em}{0ex}}.$ (11)

and

 $cos\alpha =\left(cos{𝜃}^{\prime }-cos𝜃cos\psi \right)∕\left(sin\psi sin𝜃\right)$ (12)

or

 $sin\alpha =-sin{𝜃}^{\prime }sin\left(\varphi -{\varphi }^{\prime }\right)∕sin\psi$ (13)

for and for $0\le \varphi -{\varphi }^{\prime }\le \pi$. If $\pi <\varphi -{\varphi }^{\prime }<2\pi$, then ${\alpha }^{\prime }$ and $\alpha$ are given by the negatives of these equations. The scattering angle $\psi$ is given by Eq. (9). The rotation and scattering angles depend only on the diﬀerence in azimuthal angles via $\varphi -{\varphi }^{\prime }$. Special cases are required when ${𝜃}^{\prime }$, $𝜃$, or $\psi$ are zero. For $\psi =0$, set ${\alpha }^{\prime }=\alpha =0$ since ${\varphi }^{\prime }=\varphi \phantom{\rule{3.26288pt}{0ex}}⇒\phantom{\rule{3.26288pt}{0ex}}sin\left(\varphi -{\varphi }^{\prime }\right)=0$. For $\psi =\pi$, set ${\alpha }^{\prime }=\alpha =0$ since $\varphi ={\varphi }^{\prime }+\pi \phantom{\rule{3.26288pt}{0ex}}⇒\phantom{\rule{3.26288pt}{0ex}}sin\left(\varphi -{\varphi }^{\prime }\right)=0$. If $sin{𝜃}^{\prime }=0$, replace Eqs. (10) and (12) with Hu et al. (2001)

$\begin{array}{lll}\hfill cos{\alpha }^{\prime }& =-cos{𝜃}^{\prime }cos\left(\varphi -{\varphi }^{\prime }\right)\phantom{\rule{2em}{0ex}}& \hfill \text{(14)}\\ \hfill cos\alpha & =\phantom{\rule{2.6108pt}{0ex}}cos{𝜃}^{\prime }\phantom{\rule{0.3em}{0ex}}.\phantom{\rule{2em}{0ex}}& \hfill \text{(15)}\end{array}$

If $sin𝜃=0$, replace Eqs. (10) and (12) with

$\begin{array}{lll}\hfill cos{\alpha }^{\prime }& =\phantom{\rule{2.6108pt}{0ex}}cos𝜃\phantom{\rule{2em}{0ex}}& \hfill \text{(16)}\\ \hfill cos\alpha & =-cos𝜃cos\left(\varphi -{\varphi }^{\prime }\right)\phantom{\rule{0.3em}{0ex}}.\phantom{\rule{2em}{0ex}}& \hfill \text{(17)}\end{array}$

When doing calculations of multiple scattering between sea surface wave facets, a light ray can reﬂect from one wave facet to another several times before the incident ray ﬁnally leaves the surface region and needs to be rotated into the ﬁnal meridian plane. In this case, it is more convenient to obtain the rotation angles from the perpendicular (or parallel) axes as determined for the incident ray direction onto a facet and the normal to the tilted wave facet. The details of these calculations are given in Mobley (2015) and will not be repeated here because they are not of general interest. However, it can be seen from Fig. 2 that the rotation angles can be obtained from ${cos}^{-1}\left({\mathbf{\text{v}}}^{\prime }\cdot {\mathbf{\text{p}}}^{\prime }\right)$ and ${cos}^{-1}\left(\mathbf{\text{p}}\cdot \mathbf{\text{v}}\right)$, where the dot denotes the vector dot or inner product. Figure 3 illustrates this for general initial ${\mathbf{\text{v}}}_{1}$ and ﬁnal ${\mathbf{\text{v}}}_{2}$ vectors.

Once the incident Stokes vector is speciﬁed in the scattering plane, the scattering matrix is applied to obtain the ﬁnal Stokes vector, which is then expressed in the s-p-$\xi$ scattering plane coordinate system deﬁned for the ﬁnal direction: $\mathbf{\text{s}}×\mathbf{\text{p}}=\xi$. Finally, the parallel and perpendicular components of the ﬁnal Stokes vector must be expressed as horizontal and vertical components in the ﬁnal meridian plane as speciﬁed by the h-v-$\xi$ system. As illustrated in Fig. 2, this requires a counterclockwise rotation through an angle of $\alpha$, where $\alpha$ is the “interior” angle of the spherical triangle illustrated in the ﬁgure. If $ℝ\left(\gamma \right)$ represents a counterclockwise (positive) rotation through angle $\gamma$ and $𝕄\left(\psi \right)$ represents scattering through scattering angle $\psi$, then this scattering process is symbolically represented by

 $𝕊=ℝ\left(\alpha \right)𝕄\left(\psi \right)ℝ\left({\alpha }^{\prime }\right){𝕊}^{\prime }\phantom{\rule{0.3em}{0ex}}.$ (18)

For the choice of a positive rotation being counterclockwise when looking into the beam, the Stokes vector rotation matrix is (e.g., Mishchenko et al. (2002)) page 25)

 $ℝ\left(\gamma \right)=\left[\begin{array}{cccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill cos2\gamma \hfill & \hfill -sin2\gamma \hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill sin2\gamma \hfill & \hfill cos2\gamma \hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill & \hfill 1\hfill \end{array}\right]\phantom{\rule{0.3em}{0ex}}.$ (19)

These rotation matrices have several obvious but important properties:

$\begin{array}{lll}\hfill ℝ\left(\pi \right)=& 𝕀\phantom{\rule{0.3em}{0ex}},\phantom{\rule{2em}{0ex}}& \hfill \text{(20)}\\ \hfill ℝ\left(\pi +\gamma \right)=& ℝ\left(\gamma \right)\phantom{\rule{0.3em}{0ex}},\phantom{\rule{2em}{0ex}}& \hfill \text{(21)}\\ \hfill ℝ\left(\pi -\gamma \right)=& ℝ\left(-\gamma \right)\phantom{\rule{0.3em}{0ex}},\phantom{\rule{2em}{0ex}}& \hfill \text{(22)}\\ \hfill ℝ\left(-\gamma \right)=& {ℝ}^{-1}\left(\gamma \right)={\underline{R}}^{T}\left(\gamma \right)\phantom{\rule{0.3em}{0ex}},\phantom{\rule{2em}{0ex}}& \hfill \text{(23)}\\ \hfill ℝ\left({\gamma }_{1}\right)ℝ\left({\gamma }_{2}\right)=& ℝ\left({\gamma }_{1}+{\gamma }_{2}\right)\phantom{\rule{0.3em}{0ex}}.\phantom{\rule{2em}{0ex}}& \hfill \text{(24)}\end{array}$

Equation (20) shows that rotating a coordinate system through an angle of $\pi$, which turns s and p into -s and -p leaves the Stokes vector unchanged, consistent with the previous remark about directions -s, -p being equivalent to s, p as regards Stokes vectors. That is, Stokes vectors are referred to a plane, not to a particular direction in that plane.

It is noted for completeness that a rotation in 3D space by angle $\gamma$ about an axis speciﬁed by unit vector $\mathbf{\text{u}}={u}_{x}\mathbf{\text{x}}+{u}_{y}\mathbf{\text{y}}+{u}_{z}\mathbf{\text{z}}=\left({u}_{x},{u}_{y},{u}_{x}\right)$ is

 ${R}_{3D}\left(\mathbf{\text{u}},\gamma \right)=\left[\begin{array}{ccc}\hfill cos\gamma +{u}_{x}^{2}\left(1-cos\gamma \right)\hfill & \hfill \phantom{\rule{1em}{0ex}}\phantom{\rule{1em}{0ex}}{u}_{x}{u}_{y}\left(1-cos\gamma \right)-{u}_{z}sin\gamma \hfill & \hfill \phantom{\rule{1em}{0ex}}\phantom{\rule{1em}{0ex}}{u}_{x}{u}_{z}\left(1-cos\gamma \right)+{u}_{y}sin\gamma \hfill \\ \hfill {u}_{y}{u}_{x}\left(1-cos\gamma \right)+{u}_{z}sin\gamma \hfill & \hfill \phantom{\rule{1em}{0ex}}\phantom{\rule{1em}{0ex}}cos\gamma +{u}_{y}^{2}\left(1-cos\gamma \right)\hfill & \hfill \phantom{\rule{1em}{0ex}}\phantom{\rule{1em}{0ex}}{u}_{y}{u}_{z}\left(1-cos\gamma \right)-{u}_{x}sin\gamma \hfill \\ \hfill {u}_{z}{u}_{x}\left(1-cos\gamma \right)-{u}_{y}sin\gamma \hfill & \hfill \phantom{\rule{1em}{0ex}}\phantom{\rule{1em}{0ex}}{u}_{z}{u}_{y}\left(1-cos\gamma \right)+{u}_{x}sin\gamma \hfill & \hfill \phantom{\rule{1em}{0ex}}\phantom{\rule{1em}{0ex}}cos\gamma +{u}_{z}^{2}\left(1-cos\gamma \right)\hfill \end{array}\right]$ (25)

for a counterclockwise rotation when looking in the $-\mathbf{\text{u}}$ direction. Although not needed for Stokes vector manipulations, this matrix can be used to check quantities determined by other means. For example, ${\mathbf{\text{s}}}^{\prime }={R}_{3D}\left({\xi }^{\prime },{\alpha }^{\prime }\right){\mathbf{\text{h}}}^{\prime }$ as seen in Fig. 2.

The choice of coordinate systems and rotation angles is not unique. Kattawar and Adams (1989), Kattawar (1994),Zhai et al. (2012), and Mishchenko et al. (2002)) all choose the reference plane to the be meridian plane. (These authors use somewhat diﬀerent notation; our $\mathbf{\text{h}}$ and $\mathbf{\text{v}}$ are Kattawar’s $\mathbf{\text{r}}$ and $\mathbf{\text{l}}$, respectively. Mishchenko et al. (2002)) (page 16) on the other hand use the spherical coordinate system unit vectors $𝜗$ and $\phi$ for the vertical and horizontal axes.) Thus in the ocean setting they regard the “horizontal” direction (parallel to the mean sea surface) as being the “perpendicular” direction (relative to the meridian plane), and “vertical” to the mean sea surface as being the “parallel” direction. Note in Eq. (1) that if the parallel component of the electric ﬁeld is zero, then the second element of the Stokes vector is proportional to $-{E}_{\perp }{E}_{\perp }^{\ast }=-{E}_{\perp }^{2}$, which is a negative number. A Stokes vector for light reﬂected from the sea surface with horizontal linear polarization is therefore proportional to $𝕊={\left[1,-1,0,0\right]}^{T}$, which they refer to as perpendicular polarization. Their choice of the reference plane means that the scattering (Mueller) matrix that transmits only horizontally polarized light has the form

 ${\stackrel{̃}{𝕄}}_{\text{h}}=\left[\begin{array}{cccc}\hfill 1\hfill & \hfill -1\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill -1\hfill & \hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill \end{array}\right]\phantom{\rule{0.3em}{0ex}}.$ (26)

However, Bohren and Huﬀman (1983)) and Hecht (1989) choose their “parallel” direction to be parallel to a horizontal direction, such as a laboratory bench top or the mean sea surface, and their vertical direction is perpendicular to the bench top or mean sea surface. Thus their Stokes vector for horizontal polarization (parallel to the mean sea surface) is $𝕊={\left[1,1,0,0\right]}^{T}$ and their Mueller matrix that transmits only horizontally polarized light has the form

 ${\stackrel{̃}{𝕄}}_{\text{h}}=\left[\begin{array}{cccc}\hfill 1\hfill & \hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 1\hfill & \hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill \end{array}\right]\phantom{\rule{0.3em}{0ex}}.$

The diﬀerence choices arise perhaps from the viewpoints of describing polarization in a convenient way for a laboratory experiment with reference to a table top, versus modeling light incident onto the sea surface with reference to meridian planes.

The forms of scattering matrices as commonly used to model scattering within the ocean and atmosphere are discussed on the VRTE for Mirror-symmetric Media page.

Similar confusion is found in the choice of rotation angles. Kattawar (and his students in their papers) and Bohren and Huﬀman (1983)) deﬁne a positive rotation as being clockwise when looking into the beam. Since a clockwise rotation through angle $\gamma$ is the same as a counterclockwise rotation through $-\gamma$, Kattawar’s rotation matrix is the transpose of the one in Eq. (19) (see Eq. 23). Thus Kattawar (e.g., in Eq. 10 of Kattawar and Adams (1989)) writes Eq. (18) as $𝕊=ℝ\left(-\alpha \right)𝕄\left(\psi \right)ℝ\left(-{\alpha }^{\prime }\right){𝕊}^{\prime }$ (again, with minor diﬀerences in notation; ${\alpha }^{\prime }$ here is Kattawar’s $\Phi$, etc.). Others often write a rotation as $ℝ\left(\pi -\alpha \right)$ rather than $ℝ\left(-\alpha \right)$; these are equivalent because by Eq. (19) shows that $ℝ\left(\pi -\alpha \right)=ℝ\left(-\alpha \right)$. Chandrasekhar (1960) also deﬁnes a positive rotation as being clockwise when looking into the beam. However, he uses a diﬀerent deﬁnition for the Stokes vector for which only the fourth component is independent of coordinate system, so his rotation matrix is more complicated. Mishchenko deﬁnes a positive rotation as being clockwise when looking in the direction of propagation. This is equivalent to counterclockwise when looking into the beam as used here; thus his rotation matrix is the same as that in Eq. (19). van de Hulst (1980) also uses the same rotation convention as is used here. All of this is considered “well known,” so the details are often omitted in publications, with confusing apparent diﬀerences being the price of brevity. Fortunately, the only real requirement for Stokes vectors, coordinate systems, and rotations is consistency in usage once a choice has been made.

I’ll be the ﬁrst to admit that this discussion of Stoke’s vector rotations is complicated and probably confusing. However, if you think it is bad reading about this business, just wait until you have to write a computer program to do these calculations.